Answer :

Given A.P. √2, 3√2, 5√2 …

Here, first term, a = √2

__We know that common difference, d = a _{1} – a.__

∴ d = 3√2 - √2 = 2√2

__We know that nth term of A.P. , t _{n} = a + (n – 1) d.__

⇒ t_{12} = √2 + (12 – 1) (2√2)

= √2 + 11 (2√2)

= √2 + 22 √2

= 23√2

∴ 12^{th} term of A.P. i.e. t_{12} = 23√2

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